in the problem, 2/2-y + 3/y+2 = 2y/y(2nd pwr)-4, what is the value of y?
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Hi Sammy, -------- You most probably ment: 2/(2-y) + 3/(y+2) = 2y/(y^2 -4) -------- -2(y+2) + 3(y-2) = 2y ------ -2y -4 + 3y -6 = 2y -------- -1y = -10 ------ y=10 -------- Best regards,
Do the right thing. It's good to bend, just don't bend over.
Wow, you've submitted alot of math questions. Sammy, do your own homework. That's the only way you're going to LEARN.
I am not doing this 4 ME. I'm doing it 4 a friend that doesn't have a Yedda account. I cannot help her cause i haven't taken Algebra II. So i told her i would post it so others could explain it better.
I am not doing this 4 ME. I'm doing it 4 a friend that doesn't have a Yedda account. I can't help her cause I don't know algebra II. So i told her i would post it here 2 c if any1 else could explain it better 4 her.
Thanks 4 all ur help! =)
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